By B. Carroll, D. Ostlie

**Read or Download An Introduction to Modern Astrophysics 2nd ed - SOLUTIONS MANUAL PDF**

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**Additional info for An Introduction to Modern Astrophysics 2nd ed - SOLUTIONS MANUAL **

**Sample text**

That is, for every neutral hydrogen atom in the n D 3 state, there are 19 in the n D 2 state and 3:55 109 in the n D 1 state. The number of neutral hydrogen atoms per unit area is then N1 hNa i D 5:35 1029 m 2 : N3 The ratio of the number of ionized to neutral atoms is obtained from the Saha equation, Eq. 4). The result shows that NII =NI D 1:33 10 4, so nearly all of the hydrogen atoms are neutral. Thus the above result gives the total number of hydrogen atoms per unit area, N D 5:35 1029 m 2 .

500 nm/ for each wavelength. 594 nm line: Now calculate log10 Œf . 04, so Na D 1:10 1019 m 2 . 22. 1, all of the points lie on the curve of growth. W = /. 9 nm line: Use these with the general curve of growth for the Sun, Fig. 22, to obtain a value of log10 Œf Na . =500 nm/ for each wavelength. 26. log10 Œf hNa i. W = / 4:58 4:69 3:90 4:02 Now calculate log10 Œf . 9 nm line: The average value of log10 Na for this problem is hNa i D 20:18, so hNa i D 1:51 1020 m 2 . This is the value of the number of neutral hydrogen atoms per unit area with an electron in the n D 3 orbit.

14), E1 D 13:6 eV, E2 D 3:40 eV, and E3 D 1:51 eV, and gn D 2n2 for hydrogen. 5, we find N3 =N2 D 5:14 10 2 and N3 =N1 D 2:82 10 10. That is, for every neutral hydrogen atom in the n D 3 state, there are 19 in the n D 2 state and 3:55 109 in the n D 1 state. The number of neutral hydrogen atoms per unit area is then N1 hNa i D 5:35 1029 m 2 : N3 The ratio of the number of ionized to neutral atoms is obtained from the Saha equation, Eq. 4). The result shows that NII =NI D 1:33 10 4, so nearly all of the hydrogen atoms are neutral.